1.设函数f(x)定义如下表,数列{xn}满足x0=5,且对任意自然数n均有xn+1=f(xn),则x2004的值为( )
x
|
1
|
2
|
3
|
4
|
5
|
f(x)
|
4
|
1
|
3
|
5
|
2
|
A.1 B.2
C.4 D.5
[解析] x1=f(x0)=f(5)=2,x2=f(x1)=f(2)=1,
x3=f(x2)=f(1)=4,x4=f(x3)=f(4)=5,
x5=f(x4)=f(5)=2,x6=f(x5)=f(2)=1,…
猜想f(x)是以4为周期的周期函数
∴x2004=f(x2003)=f(x3)=5.故选D.
[答案] D